Comprehension
OABC is a square where O is the origin and AB = 1. Consider the set of points S = (xi, yi) in the square such that xi + yi ≤ 1.

Let P(x1, y1) and Q(x2, y2) be two such points. Two operations addition (+) and multiplication (·) on S are defined as:

P + Q = (x1 + x2 − x1x2, y1y2)

P · Q = (x1x2,   y1 + y2 − y1y2)
Question: 1

For a very large number $n$, $P^n + Q^n$ is

Show Hint

Whenever a problem involves limits with repeated squaring ($x^n$ for $0<x<1$), the $x$-coordinate tends to 0, while transformation of $y$ pushes it towards 1. Always check asymptotic behavior before simplifying.
Updated On: Aug 25, 2025
  • close to (0,0)
  • close to (1,0)
  • close to (0,1)
  • any point in the region $x+y \leq 1$
  • None of the above
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The Correct Option is C

Solution and Explanation

Step 1: Define the points.
Let $P = (x_1, y_1)$ and $Q = (x_2, y_2)$ where $x_1, y_1, x_2, y_2 \in [0,1]$ and $x + y \leq 1$. 
Step 2: Compute $P \cdot P$.
The multiplication operation is defined as: \[ P \cdot Q = (x_1 x_2 - y_1 y_2,\; x_1 y_2 + y_1 x_2). \] So, \[ P^2 = P \cdot P = (x_1^2 - y_1^2,\; 2x_1 y_1). \] But under the constraint $x_1 + y_1 \leq 1$, this simplifies to the iterative structure: \[ P^2 = (x_1^2,\; y_1(2-y_1)). \] Step 3: Behavior as $n \to \infty$.
Since $0<x_1<1$, repeated squaring gives $x_1^n \to 0$.
Since $0<y_1<1$, repeated iteration $y_1(2-y_1)$ tends towards $1$. 
Thus, \[ P^n \to (0,1). \] Similarly, $Q^n \to (0,1)$. 
Step 4: Add the results.
\[ P^n + Q^n = (0,1) + (0,1) = (0,1). \] \[ \boxed{(0,1)} \]

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Question: 2

For a very large number $n$, $nP + nQ$ is

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When you see iterative rules like $x_{n+1} = 2x_n - x_n^2$, recognize that it converges to a stable fixed point (here, $x=1$). Meanwhile, repeated squaring of $y$ coordinates drives it to $0$.
Updated On: Aug 25, 2025
  • close to (0,0)
  • close to (1,0)
  • close to (0,1)
  • any point in the region $x+y<1$
  • None of the above
Hide Solution
collegedunia
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The Correct Option is B

Solution and Explanation

Step 1: Define the points.
Let $P = (x_1, y_1)$ and $Q = (x_2, y_2)$ in the region $x+y \leq 1$. 
Step 2: Understand $nP$.
We need to analyze repeated addition $nP = P + P + \cdots + P$ ($n$ times). The addition operation is: \[ P + Q = (x_1 + x_2 - x_1 x_2,\; y_1 y_2). \] So, \[ 2P = (2x_1 - x_1^2,\; y_1^2). \] Step 3: Behavior as $n \to \infty$.
Since $0<x_1<1$, repeated operation $x_{n+1} = 2x_n - x_n^2$ tends to $1$.
Since $0<y_1<1$, repeated squaring $y_1^n \to 0$. Thus, \[ nP \to (1,0). \] Similarly, $nQ \to (1,0)$. 
Step 4: Add the results.
\[ nP + nQ = (1,0) + (1,0) = (1,0). \] \[ \boxed{(1,0)} \]

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