Question:
Nylon-6,6 is obtained from:
Nylon-6,6 is obtained from:
Show Hint
Nylon-6,6 is a polyamide formed by the condensation polymerization of adipic acid and hexamethylene diamine. It is commonly used in textiles, plastics, and other materials.
Updated On: Mar 24, 2025
- adipic acid and hexamethylene diamine
- tetrafluoroethylene
- vinyl cyanide
- vinyl benzene
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Nylon-6,6 is a type of synthetic polymer known as a polyamide. It is formed through the condensation polymerization of two monomers: adipic acid and hexamethylene diamine. In this process, each monomer contains a functional group that reacts to form a long chain with amide linkages, resulting in the polymer known as Nylon-6,6.
- Adipic acid is a dicarboxylic acid (contains two carboxyl groups), and - Hexamethylene diamine is a diamine (contains two amine groups). These two react to form Nylon-6,6, which is widely used in textiles and engineering materials.
Thus, the correct answer is \( \boxed{{A}} \), adipic acid and hexamethylene diamine.
Was this answer helpful?
0
0
Top Questions on d -and f -Block Elements
- Number of metal ions characterized by flame test among the following is _______.
$\text{Sr}^{2+}, \text{Ba}^{2+}, \text{Ca}^{2+}, \text{Cu}^{2+}, \text{Zn}^{2+}, \text{Co}^{2+}, \text{Fe}^{2+}$- JEE Main - 2024
- Chemistry
- d -and f -Block Elements
- In the reaction of potassium dichromate, potassium chloride and sulfuric acid (conc.), the oxidation state of the chromium in the product is (+)_______.
- JEE Main - 2024
- Chemistry
- d -and f -Block Elements
- Choose the correct statements from the following:
A. \( Mn_2O_7 \) is an oil at room temperature
B. \( V_2O_4 \) reacts with acid to give \( VO_2^{2+} \)
C. \( CrO \) is a basic oxide
D. \( V_2O_5 \) does not react with acid
Choose the correct answer from the options given below:- JEE Main - 2024
- Chemistry
- d -and f -Block Elements
- A first row transition metal in its +2 oxidation state has a spin-only magnetic moment value of 3.86 BM. The atomic number of the metal is
- JEE Main - 2024
- Chemistry
- d -and f -Block Elements
- A first row transition metal with the highest enthalpy of atomisation, upon reaction with oxygen at high temperature, forms oxides of formula \( \text{M}_2\text{O}_n \) (where \( n = 3, 4, 5 \)). The 'spin-only' magnetic moment value of the amphoteric oxide from the above oxides is ___ BM (near integer).
(Given atomic number: \( \text{Sc: 21, Ti: 22, V: 23, Cr: 24, Mn: 25, Fe: 26, Co: 27, Ni: 28, Cu: 29, Zn: 30} \))- JEE Main - 2024
- Chemistry
- d -and f -Block Elements
View More Questions
Questions Asked in BITSAT exam
- Let \( ABC \) be a triangle and \( \vec{a}, \vec{b}, \vec{c} \) be the position vectors of \( A, B, C \) respectively. Let \( D \) divide \( BC \) in the ratio \( 3:1 \) internally and \( E \) divide \( AD \) in the ratio \( 4:1 \) internally. Let \( BE \) meet \( AC \) in \( F \). If \( E \) divides \( BF \) in the ratio \( 3:2 \) internally then the position vector of \( F \) is:
- BITSAT - 2024
- Vectors
- Let \( \mathbf{a} = \hat{i} - \hat{k}, \mathbf{b} = x\hat{i} + \hat{j} + (1 - x)\hat{k}, \mathbf{c} = y\hat{i} + x\hat{j} + (1 + x - y)\hat{k} \). Then, \( [\mathbf{a} \, \mathbf{b} \, \mathbf{c}] \) depends on:}
- BITSAT - 2024
- Vectors
- Let the foot of perpendicular from a point \( P(1,2,-1) \) to the straight line \( L : \frac{x}{1} = \frac{y}{0} = \frac{z}{-1} \) be \( N \). Let a line be drawn from \( P \) parallel to the plane \( x + y + 2z = 0 \) which meets \( L \) at point \( Q \). If \( \alpha \) is the acute angle between the lines \( PN \) and \( PQ \), then \( \cos \alpha \) is equal to:
- The magnitude of projection of the line joining \( (3,4,5) \) and \( (4,6,3) \) on the line joining \( (-1,2,4) \) and \( (1,0,5) \) is:
- BITSAT - 2024
- Vectors
- The angle between the lines whose direction cosines are given by the equations \( 3l + m + 5n = 0 \) and \( 6m - 2n + 5l = 0 \) is:
- BITSAT - 2024
- Vectors
View More Questions