Step 1: Energy of one photon
\[
E=\frac{hc}{\lambda}.
\]
Take
\(h=6.6\times10^{-34}\) J·s,
\(c=3\times10^8\) m/s,
\(\lambda=1000\) \AA\ = \(1\times10^{-7}\) m.
\[
E= \frac{6.6\times10^{-34}\times3\times10^8}{1\times10^{-7}}
=1.98\times10^{-18}\text{ J}.
\]
Step 2: Total energy from bulb
\[
P t = 10\times10=100\text{ J}.
\]
Step 3: Number of photons
\[
N=\frac{100}{1.98\times10^{-18}}
=5.05\times10^{19}.
\]
Step 4: Closest option (D).