Non-verbal to verbal :
Given below is a web diagram containing information about the different means of electronic devices of entertainment-some audio, some visual and some audio-visual.
Write a short paragraph based on information from the web. Give a suitable title to it. 
Modern Means of Electronic Entertainment
In today's digital age, we are surrounded by a plethora of electronic devices that provide entertainment. These can be broadly classified into three categories based on their output: audio, visual, and audio-visual. Each category offers a unique experience, catering to different preferences. Purely audio devices, which engage our sense of hearing, include portable gadgets like the iPod, as well as traditional devices like the Radio and the C.D. Player. For those who prefer visual stimulation, Video games offer an interactive and engaging experience that focuses primarily on sight. The most popular category, however, is audio-visual entertainment, which combines both sound and picture for a complete sensory experience. This category includes a wide range of devices such as the Television, Computers, DVDs, and the immersive experience of Cinema. These audio-visual mediums have become an integral part of modern life, offering everything from movies and music to educational content and interactive gaming.You are Mr. Abhishek Sharma. You are planning to celebrate your parents’ 50th wedding anniversary in a grand manner. Draft a formal invitation card for your friends and relatives. Mention all necessary details.
In the following figure \(\triangle\) ABC, B-D-C and BD = 7, BC = 20, then find \(\frac{A(\triangle ABD)}{A(\triangle ABC)}\). 
The radius of a circle with centre 'P' is 10 cm. If chord AB of the circle subtends a right angle at P, find area of minor sector by using the following activity. (\(\pi = 3.14\)) 
Activity :
r = 10 cm, \(\theta\) = 90\(^\circ\), \(\pi\) = 3.14.
A(P-AXB) = \(\frac{\theta}{360} \times \boxed{\phantom{\pi r^2}}\) = \(\frac{\boxed{\phantom{90}}}{360} \times 3.14 \times 10^2\) = \(\frac{1}{4} \times \boxed{\phantom{314}}\) <br>
A(P-AXB) = \(\boxed{\phantom{78.5}}\) sq. cm.