Step 1: Identify reduction product based on conditions.
Nitrobenzene reduction can give different products depending on medium.
In alkaline medium, partial reduction and coupling leads to azo compounds.
Step 2: Alkaline reduction produces azobenzene.
Using \(Zn/NaOH\) in presence of alcohol (methanol), nitrobenzene reduces and couples to form:
\[
C_6H_5-N=N-C_6H_5
\]
which is azobenzene.
Step 3: Why other reagents do not form azo.
\(LiAlH_4\) gives aniline.
\(Zn/NH_4Cl\) is mild acidic, gives phenylhydroxylamine/aniline.
Final Answer:
\[
\boxed{Zn/NaOH,\ CH_3OH}
\]