Solution: In the Chlor-alkali process, sodium chloride (NaCl) is electrolyzed to produce sodium hydroxide (NaOH), chlorine gas (Cl$_2$), and hydrogen gas (H$_2$):
\[2\text{NaCl (aq)} \xrightarrow{\text{electrolysis}} 2\text{NaOH (aq)} + \text{Cl}_2\text{(g)} + \text{H}_2\text{(g)}\]
- Chlorine gas (Cl$_2$) is liberated at the anode.
- Hydrogen gas (H$_2$) is liberated at the cathode.
When chlorine reacts with dry calcium hydroxide (Ca(OH)$_2$), calcium hypochlorite (Ca(OCl)$_2$) is formed:
\[\text{Ca(OH)}_2\text{(s)} + \text{Cl}_2\text{(g)} \rightarrow \text{Ca(OCl)}_2\text{(s)} + \text{H}_2\text{O(l)}\]
Calcium hypochlorite is used in water treatment and the textile industry for bleaching purposes.