1. From the first point, if Nalini's brother (say, A) is directly across from Nalini's daughter (say, C), they are on opposite sides: A is on Side 1, and C is on Side 2.
2. Now, Nalini's son is diagonally across from the worst player's sibling. This indicates that the son cannot be on the same pairing with his sibling (Nalini's daughter, C). So, Nalini's son (say, B) is therefore on Side 1, paired with Nalini's brother (A).
3. The best and the worst players are on the same side. Nalini's son, who is not mentioned directly within these constraints implying that he is neither the best nor the worst. Thus, either Nalini's brother (A) or her daughter (C) must be the best and worst players.
Four teams – Red (R), Blue (B), Green (G), and Yellow (Y) – are competing in the final four rounds of the Inter-School Science Olympiad, labeled Round A, Round B, Round C, and Round D. Each round consists of one match between two teams, and every team plays exactly two matches. No team plays the same opponent more than once.
The final schedule must adhere to the following rules:
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