Question:
Moles of $K_2SO_4$ to be dissolved in 12 moles of water to lower its vapour pressure by 10 mm Hgat a temperature at which vapour pressure of pure water is 50 mmHg is
Moles of $K_2SO_4$ to be dissolved in 12 moles of water to lower its vapour pressure by 10 mm Hgat a temperature at which vapour pressure of pure water is 50 mmHg is
Updated On: Jun 23, 2023
- 3 mol
- 2 mol
- 1 mol
- 0.5 mol
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The Correct Option is C
Solution and Explanation
$\frac{\Delta p}{p} = \frac{in_B}{in_B + n_A}$
(Please note this step)
Here $i$ = 3
$\frac{10}{50} = \frac{3n_B}{3n_B + 12}$
$3n_B + 12 = 15 \, n_B$
$12 \, n_B = 12$
$n_B = 1$
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.