Question:

Mole fraction of the solute in $1$ molal aqueous solution is

Updated On: Jul 28, 2022
  • 0.027
  • 0.036
  • 0.018
  • 0.009
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

One molal aqueous solution contains $1$ mole of the solute in $1000\, g$ of $H_2O \, i.e.$, $1000/18$ = $55.55$ moles of water $\therefore$ mole fraction of the solute = $\frac{1}{1 + 55.55}$ = $0.018$.
Was this answer helpful?
0
0

Concepts Used:

Concentration of Solutions

It is the amount of solute present in one liter of solution.

Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.

Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).

Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage

Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.

Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.

Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.

Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.

Formality - It is the number of gram formula present in one litre of solution.