Question:

Mole fraction of ethyl alcohol in aqueous ethyl alcohol solution is $0.25$. Hence percentage of ethyl alcohol by weight is

Updated On: Jul 6, 2022
  • 0.54
  • 0.25
  • 0.75
  • 0.46
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

Mole fraction of $H_2O = 1 - 0.25 = 0.75$ $\frac{x_{C_2H_5OH}}{X_{C_2H_5OH} \,+\, X_{H_2O}} = \frac{n_{_{C_2H_5OH}}}{n_{C_2H_5OH} \,+\, n_{H_2O}}$ or wt. $\% = \frac{0.25\,\times\,46}{0.25\,\times\,46\,+\,0.75\,\times\,18}\times 100 = 46\%$.
Was this answer helpful?
0
0

Top Questions on Expressing Concentration of Solutions

View More Questions

Concepts Used:

Concentration of Solutions

It is the amount of solute present in one liter of solution.

Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.

Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).

Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage

Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.

Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.

Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.

Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.

Formality - It is the number of gram formula present in one litre of solution.