Question:

Molar conductivities $(\Lambda^{\circ}_m)$ at infinite dilution of $ { NaCl, HCl}$ and $ {CH3COONa }$ are $126.4, 425.9 $ and $ {91.0 \, S\, cm^2 \, mol^{-1}}$ respectively. $(\Lambda^{\circ}_m)$ for $ {CH3COOH}$ will be:

Updated On: Jul 28, 2022
  • $\ce{ 180.5 \, S \, cm^2 \, mol^{-1} }$
  • $\ce{290.8 \, S \, cm^2 \, mol^{-1} }$
  • $\ce{ 390.5 \, S \, cm^2 \, mol^{-1} }$
  • $\ce{ 425.5 \, S \, cm^2 \, mol^{-1} }$
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The Correct Option is C

Solution and Explanation

$ {CH_3COONa + HCl -> NaCl + CH_3COOH }$ 91 + 425.9 = 126.4 + x $ {\therefore \; 390.5 \, ohm^{-1} \; cm^2 \; mol^{-1}}$
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Concepts Used:

Conductance

What is conductance?

Conductance is an expression of the ease with which electric current flows through materials like metals and nonmetals. In equations, an uppercase letter G symbolizes conductance. The standard unit of conductance is siemens (S), formerly known as mho.

What is conductance in electricity?

Conductance in electricity is considered the opposite of resistance (R). Resistance is essentially the amount of friction a component presents to the flow of current.

The conductivity of electrolytic solutions is governed by the following factors:

  • Interionic attraction
  • Solvation of ions
  • The viscosity of the solvent
  • Temperature