Molality of $2.5\, g$ of ethanoic acid $ (CH_{3}COOH) $ in $75\, g$ of benzene is
- $ 0.565\,mol \,kg^{-1} $
- $ 0.656\, mol\, kg^{-1} $
- $ 0.556\,mol\,kg^{-1} $
- $ 0.665\,mol\,kg^{-1} $
The Correct Option is C
Solution and Explanation
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Concepts Used:
Concentration of Solutions
It is the amount of solute present in one liter of solution.
Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.
Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).
Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage
Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.
Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.
Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.
Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.
Formality - It is the number of gram formula present in one litre of solution.