In linear programming, the maximum or minimum value of the objective function occurs at one of the corner points of the feasible region.
Step 1: Graph the constraints on the coordinate plane. Plot the inequalities \( 3x + 4y \leq 60 \) and \( x + y \leq 30 \), along with \( x \geq 0 \) and \( y \geq 0 \).
Step 2: Identify the feasible region formed by the intersection of the inequalities.
Step 3: The objective function is \( z = 8000x + 12000y \). To maximize \( z \), find the coordinates of the corner points of the feasible region. Step 4: Evaluate \( z \) at each corner point and select the point that gives the highest value of \( z \). Thus, the maximum value of \( z \) is obtained at the appropriate corner point.
Minimize Z = 5x + 3y \text{ subject to the constraints} \[ 4x + y \geq 80, \quad x + 5y \geq 115, \quad 3x + 2y \leq 150, \quad x \geq 0, \quad y \geq 0. \]
Solve the following L.P.P. by graphical method:
Maximize:
\[ z = 10x + 25y. \] Subject to: \[ 0 \leq x \leq 3, \quad 0 \leq y \leq 3, \quad x + y \leq 5. \]
Find the minimum value of ( z = x + 3y ) under the following constraints:
• x + y ≤ 8
• 3x + 5y ≥ 15
• x ≥ 0, y ≥ 0