Question

Match the Polymer with the most suitable Monomer combinations from which it is synthesized. \[ \begin{array}{|c|c|} \hline \text{Polymer} & \text{Monomer combinations} \\ \hline P: \text{Polyurethane} & 1: \text{Maleic acid and propylene glycol} \\ Q: \text{Epoxy} & 2: \text{Pyromellitic anhydride and p,p'-diamino diphenyl ether} \\ R: \text{Polyimide} & 3: \text{Epichlorohydrin and bisphenol A} \\ S: \text{Polyester} & 4: \text{Hexamethylene diisocyanate and tetramethylene glycol} \\ \hline \end{array} \]

• A. P-4; Q-3; R-2; S-1
• B. P-4; Q-2; R-3; S-1
• C. P-2; Q-1; R-4; S-3
• D. P-2; Q-3; R-1; S-4

Hint:

A useful memory trick: - Polyurethane → (Diisocyanate + Diol), - Epoxy → (Epichlorohydrin + Bisphenol A), - Polyimide → (Dianhydride + Diamine), - Polyester → (Acid + Glycol).

Answer 1

The Correct Option is A

Step 1: Polyurethane (P).
- Polyurethanes are formed from diisocyanates and diols. - Hexamethylene diisocyanate + tetramethylene glycol → Polyurethane. \(\Rightarrow P-4\).

Step 2: Epoxy resin (Q).
- Epoxy resins are synthesized from epichlorohydrin + bisphenol A. \(\Rightarrow Q-3\).

Step 3: Polyimide (R).
- Polyimides are made from dianhydrides + diamines. - Pyromellitic anhydride + p,p'-diamino diphenyl ether → Polyimide. \(\Rightarrow R-2\).

Step 4: Polyester (S).
- Polyesters are formed from dicarboxylic acids + glycols. - Maleic acid + propylene glycol → Polyester (alkyd-type). \(\Rightarrow S-1\).



Step 5: Combine results.
\[ P-4,\; Q-3,\; R-2,\; S-1 \] Final Answer: \[ \boxed{\text{(A) P-4; Q-3; R-2; S-1}} \]