Question:

Match the LIST-I (Element) with LIST-II (Group)
\begin{tabular}{ll} LIST-I & LIST-II
A. O\(_2\) & I. Transitional metals
B. Po & II. Non-metal
C. Os & III. Metalloid
D. Se & IV. Noble gas
\end{tabular}

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When classifying elements, remember the main blocks of the periodic table: metals on the left and center (including transition metals), a staircase of metalloids in the middle, non-metals on the right, and the noble gases in the far-right column.
Updated On: Sep 23, 2025
  • A - I, B - II, C - III, D - IV
  • A - IV, B - III, C - II, D - I
  • A - IV, B - III, C - I, D - II
  • A - III, B - IV, C - I, D - II
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The Correct Option is C

Solution and Explanation

{Note: There appears to be a typo in List-I. O\(_2\) is a molecule, not an element in the periodic table for this type of classification. Assuming O\(_2\) is a typo for a noble gas like Xenon (Xe) or Neon (Ne) makes the options solvable.} Let's proceed with the assumption A = Xe.
Step 1: Classify each element.
A. Xe (assuming O\(_2\) is a typo): Xenon is a Noble gas. So, A matches with IV.
B. Po (Polonium): Polonium is a Metalloid, having properties intermediate between metals and non-metals. So, B matches with III.
C. Os (Osmium): Osmium is a dense, hard, brittle, bluish-white Transition metal. So, C matches with I.
D. Se (Selenium): Selenium is a Non-metal. So, D matches with II.
Conclusion: The resulting match is A-IV, B-III, C-I, D-II, which corresponds to option (3).
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