Question:

Match the List-I and List-II:

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Vinylic halides have the halogen directly on a $sp^2$ carbon. Allylic halides have the halogen on a $sp^3$ carbon adjacent to a $C=C$ bond. Aryl halides have the halogen directly on the benzene ring. Benzyl halides have the halogen on the carbon adjacent to the ring.
Updated On: Jan 25, 2026
  • $\text{A} \rightarrow \text{I}, \text{B} \rightarrow \text{II}, \text{C} \rightarrow \text{III}, \text{D} \rightarrow \text{IV}$
  • $\text{A} \rightarrow \text{I}, \text{B} \rightarrow \text{II}, \text{C} \rightarrow \text{IV}, \text{D} \rightarrow \text{III}$
  • $\text{A} \rightarrow \text{III}, \text{B} \rightarrow \text{II}, \text{C} \rightarrow \text{I}, \text{D} \rightarrow \text{IV}$
  • $\text{A} \rightarrow \text{III}, \text{B} \rightarrow \text{II}, \text{C} \rightarrow \text{IV}, \text{D} \rightarrow \text{II}$
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The Correct Option is B

Solution and Explanation

We identify the corresponding structure labels (I, II, III, IV) for the given names (1, 2, 3, 4).
1. Vinyl chloride ($\text{CH}_2=\text{CH}-\text{Cl}$) $\rightarrow$ (I).
2. Allyl chloride ($\text{CH}_2=\text{CH}-\text{CH}_2-\text{Cl}$) $\rightarrow$ (II).
3. Aryl chloride ($\text{Ph}-\text{Cl}$) $\rightarrow$ (III).
4. Benzyl chloride ($\text{Ph}-\text{CH}_2-\text{Cl}$) $\rightarrow$ (IV).
The expected mapping is $1-\text{I}, 2-\text{II}, 3-\text{III}, 4-\text{IV}$.
The key provided is Option (2): $1-\text{I}, 2-\text{II}, 3-\text{IV}, 4-\text{III}$.
This implies a mismatch where Aryl (3) and Benzyl (4) names are swapped relative to structures (III) and (IV) in the option format. We select Option (2)
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