Match the following:
| List-I (Aquated ion) | List-II (Colour) |
|---|---|
| A) Ni\(^{2+}\) | V) Green |
| B) Fe\(^{3+}\) | III) Yellow |
| C) Mn\(^{3+}\) | I) Violet |
| D) V\(^{4+}\) | II) Blue |
Standard electrode potential for \( \text{Sn}^{4+}/\text{Sn}^{2+} \) couple is +0.15 V and that for the \( \text{Cr}^{3+}/\text{Cr} \) couple is -0.74 V. The two couples in their standard states are connected to make a cell. The cell potential will be:
To calculate the cell potential (\( E^\circ_{\text{cell}} \)), we use the standard electrode potentials of the given redox couples.
Given data:
\( E^\circ_{\text{Sn}^{4+}/\text{Sn}^{2+}} = +0.15V \)
\( E^\circ_{\text{Cr}^{3+}/\text{Cr}} = -0.74V \)