Question

Match the following:

I.	Zn2+	i.	d8 configuration
II.	Cu2+	ii.	colourless
III.	Ni2-	iii.	μ=1.73BM

• A. (I)-(i),(II)-(ii),(III)-(iii)
• B. (I)-(ii),(II)-(iii),(III)-(i)
• C. (I)-(ii),(II)-(i),(III)-(iii)
• D. (I)-(i),(II)-(iii),(III)-(ii)

Answer 1

The Correct Option is B

We are given the following ions and their properties. Let's match them:

Matching Species with Their Characteristics:

• I. Zn²⁺: The electronic configuration of Zn²⁺ is d¹⁰, which is colorless. It has no unpaired electrons to absorb visible light.
• II. Cu²⁺: The electronic configuration of Cu²⁺ is d⁸, which is characteristic of Cu²⁺ with a d⁸ configuration.
• III. Ni²⁺: The electronic configuration of Ni²⁺ is d⁸, and it has a magnetic moment of μ = 1.73 BM.

The correct matching is:

• I (Zn²⁺) → ii. colourless
• II (Cu²⁺) → i. d⁸ configuration
• III (Ni²⁺) → iii. μ = 1.73 BM

Therefore, the correct answer is (B).

Answer 2

- Zn²⁺ has a d⁸ configuration (no unpaired electrons, hence colorless).  
- Cu²⁺ has a colorless solution because its electronic configuration results in no unpaired electrons in the visible spectrum.  
- Ni²⁺ has a magnetic moment of 1.73 BM, indicating it has unpaired electrons (paramagnetic).  

So, the correct match is:  
I. Zn²⁺ → i. d⁸ configuration  
II. Cu²⁺ → ii. colorless  
III. Ni²⁺ → iii. μ = 1.73 BM