Question:

Match the following complexes (P) with the geometry (Q)

 P Q
a[Cu(NH3)4]2+iTetrahedral
b[Ag(NH3)2]+ iiOctahedral
cFe(CO)5iiiSquare planar
d[Cr(H2O)6]3+ivTriagonal bipyramidal
e[NiCl4]2- vLinear 

Updated On: Apr 7, 2025
  •  a)-(ii);b)-(iii);c)-(i);d)-(iv);e)-(v)

  •  a)-(iii);b)-(v);c)-(iv);d)-(ii);e)-(i)

  •  a)-(iv);b)-(iii);c)-(v);d)-(i);e)-(ii)

  •  a)-(v);b)-(iv);c)-(ii);d)-(iii);e)-(i)

  •  a)-(iv);b)-(ii);c)-(iii);d)-(v);e)-(i)

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The Correct Option is B

Approach Solution - 1

Complex Geometry Matching:

a) [Cu(NH3)4]2+:

  • Cu2+ typically forms square planar complexes
  • Matches with (iii) Square planar

 

b) [Ag(NH3)2]+:

  • Linear geometry (coordination number 2)
  • Matches with (v) Linear

 

c) Fe(CO)5:

  • Trigonal bipyramidal geometry
  • Matches with (iv) Trigonal bipyramidal

 

d) [Cr(H2O)6]3+:

  • Octahedral geometry (coordination number 6)
  • Matches with (ii) Octahedral

 

e) [NiCl4]2-:

  • Tetrahedral geometry (with weak field Cl- ligands)
  • Matches with (i) Tetrahedral

 

Correct Matching: a-(iii), b-(v), c-(iv), d-(ii), e-(i)

Thus, the correct option is (B): a) - (iii); b) - (v); c) - (iv); d) - (ii); e) - (i).

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Approach Solution -2

1. Analyze the geometry of each complex:

  • a) [Cu(NH3)4]2+:
    • Copper(II) in this complex has a \( d^9 \) electron configuration, which typically results in a square planar geometry due to the Jahn-Teller effect.
    • Geometry: Square planar (iii).
  • b) [Ag(NH3)2]+:
    • Silver(I) forms a linear complex with two ammonia ligands due to its \( d^{10} \) electron configuration and preference for minimal steric hindrance.
    • Geometry: Linear (v).
  • c) Fe(CO)5:
    • Iron in this complex is in the zero oxidation state and forms five bonds with carbon monoxide ligands. The geometry is trigonal bipyramidal due to the arrangement of the ligands around the central metal atom.
    • Geometry: Trigonal bipyramidal (iv).
  • d) [Cr(H2O)6]3+:
    • Chromium(III) in this complex has six water ligands arranged in an octahedral geometry. This is the most common geometry for complexes with six ligands.
    • Geometry: Octahedral (ii).
  • e) [NiCl4]2-:
    • Nickel(II) in this complex has four chloride ligands. Due to the weak-field nature of chloride ligands, the complex adopts a tetrahedral geometry rather than square planar.
    • Geometry: Tetrahedral (i).

2. Match the complexes with their geometries:

  • a - (iii): Square planar
  • b - (v): Linear
  • c - (iv): Trigonal bipyramidal
  • d - (ii): Octahedral
  • e - (i): Tetrahedral

3. Identify the correct option:

  • The matching corresponds to Option (B).

4. Final answer:

The correct option is (B).

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Concepts Used:

Chemical Bonding and Molecular Structure

Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.

Types of Chemical Bonds:

There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds. 

  • Ionic Bonds - Ionic bonding is a type of chemical bonding which involves a transfer of electrons from one atom or molecule to another.
  • Covalent Bonds - Compounds that contain carbon commonly exhibit this type of chemical bonding. 
  • Hydrogen Bonds -  It is a type of polar covalent bonding between oxygen and hydrogen wherein the hydrogen develops a partial positive charge
  • Polar Bonds - In Polar Covalent chemical bonding, electrons are shared unequally since the more electronegative atom pulls the electron pair closer to itself and away from the less electronegative atom.

Factors Affecting Bond Enthalpy in Chemical Bonding:

  • Size of the Atom
  • Multiplicity of Bonds
  • Number of Lone Pair of Electrons Present
  • Bond Angle