Match the following:
Matching Problem Solution:
To match the items accurately, we need to understand the relationship between the given entities.
List A | List B |
---|---|
A | III |
B | I |
C | IV |
D | II |
Explanation:
By analyzing the relationships in the table, we identify how each element in List A pairs with elements in List B:
Hence, the correct answer is A-III, B-I, C-IV, D-II, which matches the given correct option.
Step 1: Understanding the Matching Pairs - Ionization Enthalpy (A-III): The ionization enthalpy trend is \( B<Be<C<O<N \), as ionization energy increases across a period and is affected by electronic configuration.
- Metallic Character (B-I): The metallic character follows \( P<Si<Mg<Na \), as metals tend to lose electrons easily.
- Electron Gain Enthalpy (C-IV): The electron gain enthalpy follows \( I<Br<F<Cl \), as halogens have high electron affinity.
- Electronegativity (D-II): The electronegativity trend follows \( I<N<O<F \), as it increases across a period and decreases down a group.
Step 2: Evaluating the Options - Option (1): Incorrect – Incorrect assignment of electron gain enthalpy and metallic character.
- Option (2): Correct – The assignments match the given trends in periodic properties.
- Option (3): Incorrect – Incorrect placement of ionization enthalpy and electronegativity trends.
- Option (4): Incorrect – Incorrect matching of ionization enthalpy and metallic character.
Step 3: Conclusion Thus, the correct matching is A-III, B-I, C-IV, D-II, corresponding to option (2).
A 3 kg block is connected as shown in the figure. Spring constants of two springs \( K_1 \) and \( K_2 \) are 50 Nm\(^{-1}\) and 150 Nm\(^{-1}\) respectively. The block is released from rest with the springs unstretched. The acceleration of the block in its lowest position is ( \( g = 10 \) ms\(^{-2}\) )