Question

Match the following:

Ions	Properties
I. Zn2+	i. d8 configuration
II. Cu2+	ii. Colourless
III. Ni2+	iii. µ = 1.73 BM

Codes:

• A. i, ii, iii
• B. ii, iii, i
• C. ii, i, iii
• D. i, iii, ii

Hint:

Zn²⁺ is colorless (no unpaired electrons), Cu²⁺ has a magnetic moment of 1.73 BM, and Ni²⁺ has a d⁸ configuration.

Answer 1

The Correct Option is B

Let's match the given ions with their corresponding properties based on their electronic configurations and characteristics.

1. Zn²⁺: Zinc in its +2 oxidation state loses two electrons from its 4s orbitals, resulting in a configuration of [Ar] 3d¹⁰. Because the d-orbitals are completely filled, Zn²⁺ is colorless. Therefore, Zn²⁺ is paired with option ii. Colourless.
2. Cu²⁺: Copper in its +2 oxidation state loses two electrons, resulting in the electronic configuration [Ar] 3d⁹. With one unpaired electron, the magnetic moment (µ) is approximately 1.73 Bohr Magnetons (BM). Therefore, Cu²⁺ corresponds to option iii. µ = 1.73 BM.
3. Ni²⁺: Nickel in its +2 state loses two electrons, resulting in a configuration of [Ar] 3d⁸. Therefore, Ni²⁺ matches with option i. d⁸ configuration.

From the analysis above, the correct matching sequence is:

Ions	Properties
I. Zn2+	ii. Colourless
II. Cu2+	iii. µ = 1.73 BM
III. Ni2+	i. d8 configuration

Thus, the correct answer is: ii, iii, i.