Match the anti-nutritional factor in Column I with their corresponding activity given in Column II.
The correct matching of the anti-nutritional factors in Column I with their corresponding activities in Column II is as follows:
- P. Lectin matches with 4. Hemagglutination. Lectins can agglutinate red blood cells (hemagglutination) and interfere with nutrient absorption.
- Q. Stachyose matches with 1. Flatulence. Stachyose is a carbohydrate that can cause flatulence due to fermentation in the gut by bacteria.
- R. Phytate matches with 2. Chelates with divalent cations and reduces their bio-availability. Phytates bind minerals like calcium and iron, making them unavailable for absorption.
- S. Kunitz type inhibitor matches with 3. Inhibits trypsin and chymotrypsin. These inhibitors interfere with protease enzymes and reduce protein digestibility. Thus, option (A) is correct.
The \( F_{121} \) value of a known microorganism with \( Z \) value of \( 11^\circ C \) is 2.4 min for 99.9999% inactivation. For a 12D inactivation of the said microorganism at \( 143^\circ C \), the \( F \) value (in min) is .......... (rounded off to 3 decimal places)
Three villages P, Q, and R are located in such a way that the distance PQ = 13 km, QR = 14 km, and RP = 15 km, as shown in the figure. A straight road joins Q and R. It is proposed to connect P to this road QR by constructing another road. What is the minimum possible length (in km) of this connecting road?
Note: The figure shown is representative.
For the clock shown in the figure, if
O = O Q S Z P R T, and
X = X Z P W Y O Q,
then which one among the given options is most appropriate for P?