Question:
Match List - I with List IIList I List II A. Adenosine III. Nucleoside B. Adenylic acid II. Nucleotide C. Adenine I. Nitrogen base D. Alanine IV. Amino acid
Match List - I with List II
| List I | List II |
|---|---|
| A. Adenosine | III. Nucleoside |
| B. Adenylic acid | II. Nucleotide |
| C. Adenine | I. Nitrogen base |
| D. Alanine | IV. Amino acid |
Show Hint
Nucleoside = Base + Sugar. Nucleotide = Base + Sugar + Phosphate.
Updated On: May 4, 2025
- A-III, B-II, C-IV, D-I
- A-III, B-II, C-I, D-IV
- A-II, B-III, C-I, D-IV
- A-III, B-IV, C-II, D-I
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Adenosine is a nucleoside (nitrogenous base + sugar).
Adenylic acid is a nucleotide (nitrogenous base + sugar + phosphate).
Adenine is a nitrogenous base (purine).
Alanine is an amino acid.
Adenylic acid is a nucleotide (nitrogenous base + sugar + phosphate).
Adenine is a nitrogenous base (purine).
Alanine is an amino acid.
Was this answer helpful?
0
0
Top Questions on Biochemistry
Match the LIST I (Enzyme) with LIST II (Catabolic Products)
LIST-I LIST-II (Enzyme) (Catabolic Products) A \(\beta\)-galactosidase III Galactose + glucose B Lecithinase I Choline + H$_3$PO$_4$ + fat C Urease IV CO$_2$ + NH$_3$ D Lipase II Glycerol + fatty acids - What is the role of ATP in bioluminescence reactions?
- CUET (PG) - 2025
- Public Health
- Biochemistry
- A point mutation that changes a codon but does not alter the resulting amino acid is classified as -
- CUET (PG) - 2025
- Public Health
- Biochemistry
- All amino acids have a chiral centre, except
- Triple helical structure of protein is also called
View More Questions
Questions Asked in NEET exam
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
- NEET (UG) - 2025
- Pendulums
- An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen. After some oxygen is withdrawn from the cylinder, its gauge pressure drops to 11 atmospheric pressure at temperature \(27^\circ\)C. The mass of the oxygen withdrawn from the cylinder is nearly equal to: [Given, \(R = \frac{100}{12} \text{ J mol}^{-1} \text{K}^{-1}\), and molecular mass of \(O_2 = 32 \text{ g/mol}\), 1 atm pressure = \(1.01 \times 10^5 \text{ N/m}^2\)]
- NEET (UG) - 2025
- Ideal-gas equation and absolute temperature
- A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of \(60^\circ\) with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (take \(g = 10\) m/s\(^2\)):
- NEET (UG) - 2025
- Common forces in mechanics
- A wire of resistance \(R\) is cut into 8 equal pieces. From these pieces, two equivalent resistances are made by adding four of these together in parallel. Then these two are added in series. The net effective resistance of the combination is:
- NEET (UG) - 2025
- Resistance
- Which of the following organisms cannot fix nitrogen? A. Azotobacter
B. Oscillatoria
C. Anabaena
D. Volvox
E. Nostoc
Choose the correct answer from the options given below:- NEET (UG) - 2025
- Nitrogen Fixation
View More Questions