88 g of CO\(_2\) corresponds to 2 moles. \( 6.023 \times 10^{23} \) molecules of H\(_2\)O is 1 mole. 96 g of O\(_2\) corresponds to 3 moles. 1 mol of any gas occupies 22.4 L at STP, which is \( 6.023 \times 10^{23} \) molecules.
Was this answer helpful?
0
0
Top Questions on Stoichiometry and Stoichiometric Calculations