Match List I with List II LIST I LIST II A. 88 g of CO 2 I. 2 mol B. 6.023 × 10 23 molecules of H 2 O II. 1 mol C. 96 g of O 2 III. 6.023 × 10 23 molecules D. 1 mol of any gas IV. 3 mol Choose the correct answer from the options given below:

(A)- (I), (B)- (II), (C)- (IV), (D)- (III)

Match List I with List II LIST I LIST II A. 88 g of CO 2 I. 2 mol B. 6.023 × 10 23 molecules of H 2 O II. 1 mol C. 96 g of O 2 III. 6.023 × 10 23 molecules D. 1 mol of any gas IV. 3 mol Choose the correct answer from the options given below:}

(A)- (I), (B)- (II), (C)- (IV), (D)- (III)

(A)- (III), (B)- (II), (C)- (I), (D)- (IV)

(A)- (II), (B)- (I), (C)- (III), (D)- (IV)

(A)- (II), (B)- (III), (C)- (I), (D)- (IV)

Question:

Match List I with List II
LIST I LIST II
A. 88 g of CO₂ I. 2 mol
B. 6.023 × 10²³ molecules of H₂O II. 1 mol
C. 96 g of O₂ III. 6.023 × 10²³ molecules
D. 1 mol of any gas IV. 3 mol
Choose the correct answer from the options given below:

LIST I	LIST II
A. 88 g of CO₂	I. 2 mol
B. 6.023 × 10²³ molecules of H₂O	II. 1 mol
C. 96 g of O₂	III. 6.023 × 10²³ molecules
D. 1 mol of any gas	IV. 3 mol

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To convert mass into moles, use the molar mass of the substance, and for molecules, use Avogadro’s number to convert between molecules and moles.

Updated On: Mar 13, 2025

(A)- (I), (B)- (II), (C)- (IV), (D)- (III)
(A)- (III), (B)- (II), (C)- (I), (D)- (IV)
(A)- (II), (B)- (I), (C)- (III), (D)- (IV)
(A)- (II), (B)- (III), (C)- (I), (D)- (IV)

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The Correct Option is A

Solution and Explanation

88 g of CO\(_2\) corresponds to 2 moles. \( 6.023 \times 10^{23} \) molecules of H\(_2\)O is 1 mole. 96 g of O\(_2\) corresponds to 3 moles. 1 mol of any gas occupies 22.4 L at STP, which is \( 6.023 \times 10^{23} \) molecules.

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Match List I with List IILIST ILIST IIA. 88 g of CO2I. 2 molB. 6.023 × 1023 molecules of H2OII. 1 molC. 96 g of O2III. 6.023 × 1023 moleculesD. 1 mol of any gasIV. 3 molChoose the correct answer from the options given below:

Show Hint

The Correct Option is A

Solution and Explanation

Top Questions on Stoichiometry and Stoichiometric Calculations

Questions Asked in CUET PG exam

Match List I with List II
LIST I LIST II
A. 88 g of CO₂ I. 2 mol
B. 6.023 × 10²³ molecules of H₂O II. 1 mol
C. 96 g of O₂ III. 6.023 × 10²³ molecules
D. 1 mol of any gas IV. 3 mol
Choose the correct answer from the options given below: