List-I ( Types of hybridisation ) | List-II ( Distribution of hybrid orbitals in space ) | ||
A | sp$^3$ | (I) | Trigonal bipyramidal |
B | dsp$^2$ | (II) | Octahedral |
C | sp$^3$d | (III) | Tetrahedral |
D | sp$^3$d$^2$ | (IV) | Square Planar |
To solve the problem of matching the types of hybridization with their corresponding distribution of hybrid orbitals in space, we need to understand the characteristics of each hybrid and its typical geometry.
The correct matching is therefore:
Therefore, the correct answer is: A-III, B-IV, C-I, D-II.
The correct matches are:
These arrangements are based on the number of bonding and lone pairs around the central atom. The geometry is influenced by the concept of VSEPR theory (Valence Shell Electron Pair Repulsion theory), which states that electron pairs around a central atom arrange themselves to minimize repulsion, leading to specific molecular shapes.
For example:
Concentrated nitric acid is labelled as 75% by mass. The volume in mL of the solution which contains 30 g of nitric acid is:
Given: Density of nitric acid solution is 1.25 g/mL.
Arrange the following in increasing order of solubility product:
\[ {Ca(OH)}_2, {AgBr}, {PbS}, {HgS} \]
Match List - I with List - II.
List - I (Saccharides) List - II (Glycosidic linkages found)
(A) Sucrose (I) \( \alpha 1 - 4 \)
(B) Maltose (II) \( \alpha 1 - 4 \) and \( \alpha 1 - 6 \)
(C) Lactose (III) \( \alpha 1 - \beta 2 \)
(D) Amylopectin (IV) \( \beta 1 - 4 \)
Choose the correct answer from the options given below: