Question:

Match List I with List II
 List I  List II
A2n+12^{n+1}Iω(n)
B22n2^{2n}II0(2n)
C2n22^\frac{n}{2}{}IIIω(2n)
Dnnn^nIV0(2n)

Updated On: Mar 16, 2024
  • A-I, B-III, C-IV, D-II
  • A-II, B-III, C-IV, D-I
  • A-1, B-II, C-III, D-IV
  • A-IV, B-III, C-II, D-I
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The Correct Option is D

Solution and Explanation

The correct option is(D): A-IV, B-III, C-II, D-I
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