Match List I with List II
| List I (Cells) | List II (Secretion) | ||
| A | Peptic cells | I | Mucus |
| B | Goblet cells | II | Bile juice |
| C | Oxyntic cells | III | Proenzyme pepsinogen |
| D | Hepatic cells | IV | HCl and intrinsic factor for absorption of vitamin B12 |
Choose the correct answer from the options given below:
To solve the problem, we need to match the cells listed in List I with their respective secretions in List II. Here is the breakdown of each cell type and their associated secretions:
Based on the above understanding, the correct matching is:
Therefore, the correct answer is:
| List I | List II | ||
| A | Lipase | I | Peptide bond |
| B | Nuclease | II | Ester bond |
| C | Protease | III | Glycosidic bond |
| D | Amylase | IV | Phosphodiester bond |
A constant voltage of 50 V is maintained between the points A and B of the circuit shown in the figure. The current through the branch CD of the circuit is :
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
What is Microalbuminuria ?