List I | List II | ||
A | Lipase | I | Peptide bond |
B | Nuclease | II | Ester bond |
C | Protease | III | Glycosidic bond |
D | Amylase | IV | Phosphodiester bond |
- Lipase (A) acts on the ester bond in lipids (II).
- Nuclease (B) cleaves the phosphodiester bond in nucleic acids (IV).
- Protease (C) breaks down peptide bonds in proteins (I).
- Amylase (D) acts on the glycosidic bond in carbohydrates (III)
Matching Enzymes with Their Functions:
A. Lipase – Breaks ester bonds.
Matches with: II. Breaks ester bonds.
B. Nuclease – Breaks phosphodiester bonds.
Matches with: IV. Breaks phosphodiester bonds.
C. Protease – Breaks peptide bonds.
Matches with: I. Breaks peptide bonds.
D. Amylase – Breaks glycosidic bonds.
Matches with: III. Breaks glycosidic bonds.
Thus, the correct answer is (3) A-II, B-IV, C-I, D-III.
Match List I with List II
List I (Cells) | List II (Secretion) | ||
A | Peptic cells | I | Mucus |
B | Goblet cells | II | Bile juice |
C | Oxyntic cells | III | Proenzyme pepsinogen |
D | Hepatic cells | IV | HCl and intrinsic factor for absorption of vitamin B12 |
Choose the correct answer from the options given below:
List I (Spectral Lines of Hydrogen for transitions from) | List II (Wavelength (nm)) | ||
A. | n2 = 3 to n1 = 2 | I. | 410.2 |
B. | n2 = 4 to n1 = 2 | II. | 434.1 |
C. | n2 = 5 to n1 = 2 | III. | 656.3 |
D. | n2 = 6 to n1 = 2 | IV. | 486.1 |
The following diagram shown restriction sites in E. coli cloning vector pBR322. Find the role of ‘X’ and ‘Y’gens :