Question:
Match List-I with List-Il: List-I List-II A. Coke I. Carbon atoms are sp3 hybridized. B. Diamond II. Used as a dry lubricant. C. Fullerene III. Used as a reducing agent. D. Graphite IV. Cage like molecules
Choose the correct answer from the options given below:
Match List-I with List-Il:
| List-I | List-II | ||
| A. | Coke | I. | Carbon atoms are sp3 hybridized. |
| B. | Diamond | II. | Used as a dry lubricant. |
| C. | Fullerene | III. | Used as a reducing agent. |
| D. | Graphite | IV. | Cage like molecules |
Choose the correct answer from the options given below:
Updated On: May 1, 2025
- A-lV, B-I, C-II, D-III
- A-III, B-I, C-IV, D-II
- A-llI, B-IV, C-I, D-II
- A-II, B-IV, C-I, D-III
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The Correct Option is B
Approach Solution - 1
To solve the given problem, we need to match the items in List-I with their corresponding descriptions in List-II based on the properties of those substances.
| List-I | List-II | ||
| A. | Coke | I. | Carbon atoms are sp3 hybridized. |
| B. | Diamond | II. | Used as a dry lubricant. |
| C. | Fullerene | III. | Used as a reducing agent. |
| D. | Graphite | IV. | Cage like molecules |
Let's match each item:
- Coke: Used as a reducing agent, typically in metallurgical processes. Therefore, Coke matches with III.
- Diamond: In diamond, carbon atoms are sp3 hybridized and form a very hard structure. Thus, Diamond matches with I.
- Fullerene: Fullerene molecules have a cage-like structure. Hence, Fullerene corresponds with IV.
- Graphite: Known for its layered structure, Graphite is used as a dry lubricant. So, Graphite matches with II.
Therefore, the correct matching is:
A-III, B-I, C-IV, D-II
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Approach Solution -2
Coke: In carbon reduction techniques, it serves as a reducing agent.
Diamond: Each carbon atom in a diamond is sp3 hybridized, making it an allotrope of carbon.
Fullerene: Pentagonal and hexagonal rings (a structure resembling a cage) are present in fullerene.
Graphite: Because graphite layers are joined together by feeble Vander Wall attractions, it is a soft solid.
Therefore, The correct option is (B): A-III, B-I, C-IV, D-II
Diamond: Each carbon atom in a diamond is sp3 hybridized, making it an allotrope of carbon.
Fullerene: Pentagonal and hexagonal rings (a structure resembling a cage) are present in fullerene.
Graphite: Because graphite layers are joined together by feeble Vander Wall attractions, it is a soft solid.
Therefore, The correct option is (B): A-III, B-I, C-IV, D-II
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- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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