Match List I with List II:
List I | List II |
---|---|
A. Spinal poison | I. Carbon monoxide |
B. NH2- | II. Linear |
C. NH4+ | III. Tetrahedral |
D. [PtCl4]- | IV. Square planar |
Choose the correct answer from the options given below:
\(\text{ICl}_2^-\) has a linear shape.
\(\text{NH}_2^-\) has a V-shape (angular).
\(\text{NH}_4^+\) has a tetrahedral shape.
\([\text{PtCl}_4]^-\) has a square planar shape.
Assertion (A): [Cr(H_2O)_6]Cl_2 and [Fe(H_2O)_6]Cl_2 are examples of homoleptic complexes. Reason (R): All the ligands attached to the metal are the same.
Low spin tetrahedral complexes are not known.
Co2+ is easily oxidized to Co3+ in the presence of a strong ligand (At. No. of Co = 27).
Why is a solution of \(\text{Ni(H}_2\text{O})_6^{2+}\) green while a solution of \(\text{Ni(CN)}_4^{2-}\) is colourless? (At. No. of Ni = 28)
The color of a coordination complex depends on the d–d transitions in the visible region of the spectrum, which are influenced by the ligand field strength.
- In \(\text{Ni(H}_2\text{O})_6^{2+}\), Ni\(^{2+}\) has an electronic configuration of \([Ar]3d^8\). Water (\(\text{H}_2\text{O}\)) is a weak field ligand, causing a small crystal field splitting (\(\Delta\)), allowing d–d transitions in the visible region, which results in a green color.
- In \(\text{Ni(CN)}_4^{2-}\), cyanide (\(\text{CN}^-\)) is a strong field ligand,