Question

Match List-I with List-II\[ \begin{array}{|c|c|} \hline \textbf{Type of fluids} & \textbf{Relationship between shear stress and velocity gradient} \\ \hline (A) \text{Newtonian fluid} & (III) \text{Linear} \\ (B) \text{Non-Newtonian fluid} & (IV) \text{Non-linear} \\ (C) \text{Ideal Fluid} & (I) \text{Zero velocity gradient} \\ (D) \text{Ideal Plastic} & (II) \text{With definite yield stress and linear relationship} \\ \hline \end{array} \]

• (A) - (I), (B) - (IV), (C) - (III), (D) - (II)
• (A) - (IV), (B) - (II), (C) - (III), (D) - (I)
• (A) - (III), (B) - (III), (C) - (II), (D) - (IV)
• (A) - (II), (B) - (IV), (C) - (I), (D) - (II)

Hint:

Newtonian fluids have a linear relationship between shear stress and velocity gradient, whereas Non-Newtonian fluids exhibit more complex, non-linear behavior.

Answer 1

The Correct Option is A

Step 1: Understanding the fluids and their characteristics.
- (A) Newtonian fluid: A fluid where the relationship between shear stress and velocity gradient is linear, with constant viscosity, and a zero velocity gradient at no flow. - (B) Non-Newtonian fluid: The relationship between shear stress and velocity gradient is non-linear, and they have a definite yield stress. - (C) Ideal Fluid: This fluid is assumed to have a linear relationship between shear stress and velocity gradient, but is an idealized concept. - (D) Ideal Plastic: For this fluid, the relationship is non-linear, with a definite yield stress.
Step 2: Matching the relationships.
- (A) Newtonian fluid: Matches with (I) Zero velocity gradient (because at no flow, the velocity gradient is zero). - (B) Non-Newtonian fluid: Matches with (IV) Non-linear relationship. - (C) Ideal Fluid: Matches with (III) Linear relationship. - (D) Ideal Plastic: Matches with (II) Non-linear with definite yield stress.
Step 3: Conclusion.
Therefore, the correct matching is (1) (A) - (I), (B) - (IV), (C) - (III), (D) - (II).