List-I | List-II |
A. China rose | I. Free central |
B. Mustard | II. Basal |
C. Primrose | III. Axile |
D. Marigold | IV. Parietal |
The correct matches based on the type of placentation are:
Therefore, the correct option is (3): A-III, B-IV, C-I, D-II.
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec: