Question:

Match List-I with List-II.
reactions and products
Choose the correct answer from the options given below :

Updated On: Nov 4, 2025
  • (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
  • (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
  • (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
  • (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
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The Correct Option is D

Approach Solution - 1

To solve the problem, we need to match the reactions in List-I with the correct products from List-II based on well-known organic chemistry reactions. Let's go through each reaction step-by-step:

  1. (A) Reaction: Benzene with an amino group (NH2) is treated with NaNO2 + HCl followed by warm H2O. This is a well-known diazotization reaction that converts aniline to phenol. In this case, however, it forms a benzene with an aldehyde at the para position. Thus, this matches with (II).
  2. (B) Reaction: Phenol (OH group) is oxidized by Na2Cr2O7 / H2SO4. This oxidizes the alcohol to a carboxylic acid. Therefore, the product is benzoic acid (with the carboxylic group), which matches with (IV).
  3. (C) Reaction: Phenol is treated with CHCl3 + aq NaOH followed by H+. This is the Reimer-Tiemann reaction, which forms salicylic acid (with a carboxyl group adjacent to the phenol group). Thus, this matches with (I).
  4. (D) Reaction: Phenol is treated with NaOH, then CO2, and finally H+. This results in the Kolbe-Schmitt reaction, forming salicylic acid (with the carboxyl group para to the phenol group). This corresponds with (III).

Thus, the correct matching is (A)-(II), (B)-(IV), (C)-(I), (D)-(III). This matches the provided correct answer.

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Approach Solution -2

Solution 67

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