Question

Match List-I with List-II 



Choose the correct answer from the options given below:

• (A) (II), (B) (I), (C) (IV), (D) (III)
• (A) (I), (B) (III), (C) (II), (D) (IV)
• (A) (I), (B) (II), (C) (IV), (D) (III)
• (A) (III), (B) (IV), (C) (I), (D) (II)

Hint:

Ethyl bromide undergoes S\(_N\)2, tertiary-butyl bromide undergoes S\(_N\)1, acetone reacts via nucleophilic addition, and benzene undergoes electrophilic substitution.

Answer 1

The Correct Option is C

- Ethyl bromide (A) undergoes S\(_N\)2 reaction (bimolecular nucleophilic substitution) because it is a primary alkyl halide.
- Tertiary butyl bromide (B) undergoes S\(_N\)1 reaction (unimolecular nucleophilic substitution) due to the stable carbocation formed.
- Acetone (C) reacts with nucleophiles via nucleophilic addition due to the presence of a carbonyl group.
- Benzene (D) is reactive towards electrophilic substitution because of its aromatic nature.
Step 2: Conclusion.
Thus, the correct matching is: \[ \text{(A) (I), (B) (II), (C) (IV), (D) (III)} \]
Final Answer: \[ \boxed{\text{(A) (I), (B) (II), (C) (IV), (D) (III)}} \]