Question

Match List-I with List-II.\[\begin{array}{|c|c|} \hline \textbf{List-I (Letter number series)} & \textbf{List-II (Missing term)} \\ \hline \text{(A) D4,F6,H8,J10} & \text{(I) U121} \\ \hline \text{(B) 2B,4C,8E,14H, ?} & \text{(II) 11I} \\ \hline \text{(C) 3F,6G, ?,18L,27P} & \text{(III) 22L} \\ \hline \text{(D) W144, ?,S100,Q81,O64} & \text{(IV) L12} \\ \hline \end{array}\]

• (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
• (A) - (II), (B) - (I), (C) - (III), (D) - (IV)
• (A) - (IV), (B) - (III), (C) - (I), (D) - (II)
• (A) - (IV), (B) - (II), (C) - (III), (D) - (I)

Hint:

When dealing with letter-number sequences, break down the series by examining the patterns in both the numbers and the letter positions.

Answer 1

The Correct Option is D

Step 1: Analyze each number series.
- (A) \( D4, F6, H8, J10, ? \): The letters follow a pattern: D (4), F (6), H (8), J (10), and the next letter is L with the number 12. Therefore, this matches with List-II option IV (L12).
- (B) \( 2B, 4C, 8E, 14H, ? \): The numbers double each time (2, 4, 8, 14...), and the corresponding letter positions increase in a similar fashion (B, C, E, H...). The next number is 28 and the letter is L, matching with List-II option II (111).
- (C) \( 3F, 6G, ?, 18L, 27P \): Here, the number doubles (3, 6, 12, 18...) and the letters follow the alphabetical order (F, G, I, L, P...). The missing term is 12 and the letter is I, which corresponds to List-II option III (22L).
- (D) \( W144, S100, Q81, O64 \): The numbers decrease by a fixed pattern: 144, 100, 81, 64... The next term is 49 with the letter M, corresponding to List-II option I (U121).

Step 2: Conclusion.
Thus, the correct matching is: (A) - (IV), (B) - (II), (C) - (III), (D) - (I).