Question:

Match amplifier class with its conduction cycle:

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Conduction angle determines amplifier class: A = 360°, B = 180°, AB ≈ 200–300°, C<180°.
Updated On: Jun 12, 2025
  • A–R, B–P, C–Q, D–S
  • A–R, B–P, C–S, D–Q
  • A–S, B–R, C–P, D–Q
  • A–R, B–S, C–Q, D–P
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The Correct Option is B

Solution and Explanation

In the context of amplifier classes based on their conduction cycles, an understanding of each class helps in identifying the correct matches for their operational cycles: 

  • Class A: Conducts for the entire input cycle (360 degrees). This corresponds to the conduction cycle where current flows for the entire signal, without cutoff. Hence, A–R.
  • Class B: Conducts for half of the input cycle (180 degrees). This amplifier operates only during half of the waveform, hence B–P.
  • Class AB: Conducts for more than half but less than the entire input cycle. The current flows for more than 180 degrees but less than 360 degrees, hence C–S.
  • Class C: Conducts for less than half of the input cycle. This class operates at a conduction angle of less than 180 degrees, hence D–Q.

The correct matching of amplifier classes with their conduction cycles is therefore: A–R, B–P, C–S, D–Q.

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