Step 1: Understand the effect of Wolbachia on the host population.
Wolbachia are maternally inherited bacteria that can affect host fitness in different ways. Some effects include cytoplasmic incompatibility (CI), which causes incompatible crosses between infected and uninfected individuals, increasing the spread of Wolbachia.
Step 2: Analyzing the options.
Option (A) describes Wolbachia inducing cytoplasmic incompatibility, which is a key mechanism that allows Wolbachia to spread by preventing the successful reproduction of uninfected females and infected males.
Option (B) describes an increase in the fecundity (reproductive success) of the host, which also helps Wolbachia spread.
Option (C) describes an increase in the immune response, which could lead to a fitness advantage for infected hosts, helping Wolbachia persist in the population.
Option (D) describes cytoplasmic compatibility, where mating between infected and uninfected individuals produces viable offspring. This would reduce the spread of Wolbachia because the incompatibility is key to its spread.
Thus, the correct answer is (D) because cytoplasmic compatibility would allow uninfected individuals to reproduce successfully with infected individuals, reducing Wolbachia's spread.
The 12 musical notes are given as \( C, C^\#, D, D^\#, E, F, F^\#, G, G^\#, A, A^\#, B \). Frequency of each note is \( \sqrt[12]{2} \) times the frequency of the previous note. If the frequency of the note C is 130.8 Hz, then the ratio of frequencies of notes F# and C is:
Here are two analogous groups, Group-I and Group-II, that list words in their decreasing order of intensity. Identify the missing word in Group-II.
Abuse \( \rightarrow \) Insult \( \rightarrow \) Ridicule
__________ \( \rightarrow \) Praise \( \rightarrow \) Appreciate