Question:

Major product ‘B’ of the following reaction sequence is

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The correct answer is (B):
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Updated On: Jan 2, 2026
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The Correct Option is B

Solution and Explanation

To determine the major product 'B' of the given reaction sequence, we need to analyze each step: 

  1. The initial compound is an alkene, which is treated with \(Br_2\) in methanol \((\text{CH}_3\text{OH})\). This is a halogenation reaction in which the alkene reacts with bromine to form a vicinal dihalide.
  2. Methanol acts as a nucleophile here and attacks the more substituted carbon, leading to the formation of a bromomethoxy compound.
  3. The second step involves the treatment of this bromomethoxy compound with hydrogen iodide \((\text{HI})\).
  4. \(HI\) is a strong acid and also provides the iodide nucleophile. It reacts with the bromomethoxy compound to replace the methoxy group with an iodide, primarily through an \(S_N2\) mechanism.
  5. Thus, the major product 'B' formed will have iodine attached in place of the methoxy group.

Considering these steps, the major product 'B' is an iodo-alkane. Below is the correct option representing the major product:

This represents the structure of 'B' correctly as the iodo-alkane formed after the reaction steps described above.

The correct answer is (B)

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Concepts Used:

Aldehydes, Ketones and Carboxylic Acids - Chemical Reactions

Chemical Reactions of Aldehydes and Ketones:

Nucleophilic Addition Reactions
Nucleophilic Addition Reactions
Tollens’ test
Tollens’ Test
Fehling’s test
Fehling’s Test
Aldol condensation
Aldol Condensation
  • Cross aldol condensation
Cross aldol condensation
Cross Aldol Condensation
Cannizzaro reaction
Cannizzaro Reaction
Electrophilic Substitution Reaction
Electrophilic Substitution Reaction

Read Also: Aldehydes, Ketones, and Carboxylic Acids

Fischer Esterification
Fischer Esterification
Decarboxylation
Decarboxylation
Halogenation
Halogenation

Read More: Chemistry Named Reactions