Question:
Magnitude of error in the determination of the integral, I using Simpson's 1/3 rule, taking step length as 1.0 is
\(I=∫^3_1(x^3+6)\) dx
Magnitude of error in the determination of the integral, I using Simpson's 1/3 rule, taking step length as 1.0 is
\(I=∫^3_1(x^3+6)\) dx
\(I=∫^3_1(x^3+6)\) dx
Updated On: Jul 18, 2024
- 0
- 1.0
- 1.5
- 2.0
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The Correct Option is A
Solution and Explanation
The correct option is (A): 0
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