Question:
Magnetic energy density in an inductor is given by
Magnetic energy density in an inductor is given by
Updated On: Jun 2, 2024
- $ U_{B}=B^{2}/2\mu_{0} $
- $ U_{B}=B^{2} \times 2\mu_{0} $
- $ U_{B}=2B^{2}/\mu_{0} $
- $ U_{B}=B^{2}+2\mu_{0} $
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The Correct Option is A
Solution and Explanation
Magnetic energy density in the inductor is
$U_{B}=\frac{B^{2}}{2 \mu_{0}}$
$U_{B}=\frac{B^{2}}{2 \mu_{0}}$
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter