Question:
Locus of the point of intersection of perpendicular tangents to the circle $x^2 + y^2 = 16 $ is
Locus of the point of intersection of perpendicular tangents to the circle $x^2 + y^2 = 16 $ is
Updated On: Jul 6, 2022
- $x^2 + y^2 = 8 $
- $x^2 + y^2 = 32 $
- $ x^2 + y^2 = 64$
- $x^2 + y^2 = 16. $
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The Correct Option is B
Solution and Explanation
Answer (b) $x^2 + y^2 = 32 $
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