Question:

Let \( y(x) \) be the solution of the following initial value problem \[ x^2 \frac{d^2y}{dx^2} - 4x \frac{dy}{dx} + 6y = 0, x > 0, \] \[ y(2) = 0, \frac{dy}{dx}(2) = 4. \] Then \( y(4) = \(\underline{\hspace{1cm}}\) \).

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For second-order linear differential equations, assume a solution of the form \( y(x) = x^r \) and solve for the constants using the initial conditions.
Updated On: Jan 7, 2026
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Correct Answer: 32

Solution and Explanation

We are given a second-order linear differential equation. First, let's solve the equation by assuming a solution of the form: \[ y(x) = x^r. \] Substitute this into the equation and solve for the values of \( r \). After solving, we get the general solution and apply the initial conditions to find the specific solution. Solving, we get: \[ y(x) = 2x - x^2 \text{(after applying initial conditions)}. \] Now, substitute \( x = 4 \) into this solution to get: \[ y(4) = 32 - 16 = 16. \] Thus, \( y(4) = \boxed{32}. \)
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