Question:
Let \( X_1, X_2, \dots, X_n \) be a random sample of size \( n \) from a population having probability density function
\[
f(x; \mu) =
\begin{cases}
e^{-(x-\mu)} & \text{if } \mu \leq x < \infty \\
0 & \text{otherwise}
\end{cases}
\]
where \( \mu \in \mathbb{R} \) is an unknown parameter. If \( \hat{M} \) is the maximum likelihood estimator of the median of \( X_1 \), then which one of the following statements is true?
Let \( X_1, X_2, \dots, X_n \) be a random sample of size \( n \) from a population having probability density function
\[
f(x; \mu) =
\begin{cases}
e^{-(x-\mu)} & \text{if } \mu \leq x < \infty \\
0 & \text{otherwise}
\end{cases}
\]
where \( \mu \in \mathbb{R} \) is an unknown parameter. If \( \hat{M} \) is the maximum likelihood estimator of the median of \( X_1 \), then which one of the following statements is true?
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- Maximum likelihood estimation (MLE) is used to find the most likely parameter estimates based on observed data.
- In this case, we estimate the median of the exponential distribution using MLE.
- In this case, we estimate the median of the exponential distribution using MLE.
Updated On: Aug 30, 2025
- \( P(\hat{M} \leq 2) = 1 - e^{-n(1 - \log 2)} \text{ if } \mu = 1 \)
- \( P(\hat{M} \leq 1) = 1 - e^{-n \log 2} \text{ if } \mu = 1 \)
- \( P(\hat{M} \leq 3) = 1 - e^{-n(1 - \log 2)} \text{ if } \mu = 1 \)
- \( P(\hat{M} \leq 4) = 1 - e^{-n(2 \log e 2 - 1)} \text{ if } \mu = 1 \)
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The Correct Option is A
Solution and Explanation
The maximum likelihood estimator for the median of the exponential distribution is derived by maximizing the likelihood function for the given probability density function. By calculating the cumulative distribution function and solving the likelihood equation, we find that the maximum likelihood estimator for the median satisfies the given relation, leading to the correct answer. The probability expression in option (A) corresponds to the proper form of the likelihood equation for \( \hat{M} \).
The correct answer is (A) \( P(\hat{M} \leq 2) = 1 - e^{-n(1 - \log 2)} \).
The correct answer is (A) \( P(\hat{M} \leq 2) = 1 - e^{-n(1 - \log 2)} \).
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