Question:

Let the probability distribution of random variable X be
X-2-1123
P(X=x)k2k2kk3k

Then, the value of E(X2) is

Updated On: Jun 10, 2024
  • \(\frac{19}{9}\)
  • \(\frac{13}{3}\)
  • \(\frac{35}{9}\)
  • \(\frac{11}{3}\)
  • \(\frac{7}{3}\)
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The Correct Option is B

Solution and Explanation

The correct option is (B): \(\frac{13}{3}\)
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