Given the position vectors of the vertices of the triangle, we use the properties of centroid and orthocenter to calculate the required sum \( \alpha + 2\beta + 5\gamma \).
Final Answer: \( \alpha + 2\beta + 5\gamma = 3 \).
Match List - I with List - II.
In the given structure, number of \( sp \) and \( sp^2 \) hybridized carbon atoms present respectively are: