Question:

Let f(x) = x2 and \(g(x) = \sqrt{9+x}\). Then the value of \((f^\circ g-g^\circ f)(4)\) is equal to

Updated On: Apr 4, 2025
  • 6
  • √6
  • √8
  • 8
  • 5
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The Correct Option is D

Solution and Explanation

We are given the functions:

  • \( f(x) = x^2 \) 
  • \( g(x) = \sqrt{9 + x} \)

We need to find the value of \( (f \circ g - g \circ f)(4) \). This represents the difference between the composition of \( f \) and \( g \) and the composition of \( g \) and \( f \) evaluated at \( x = 4 \).

First, let's compute \( f \circ g \) and \( g \circ f \):

  • \( (f \circ g)(x) = f(g(x)) = f(\sqrt{9 + x}) = (\sqrt{9 + x})^2 = 9 + x \)
  • \( (g \circ f)(x) = g(f(x)) = g(x^2) = \sqrt{9 + x^2} \)

Now, we compute the value of \( (f \circ g - g \circ f)(4) \):

  • \( (f \circ g)(4) = 9 + 4 = 13 \)
  • \( (g \circ f)(4) = \sqrt{9 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \)

Therefore, \( (f \circ g - g \circ f)(4) = 13 - 5 = 8 \).

The correct answer is 8.

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