\(-1\)
\(\pi\)
\(-\pi\)
\(0\)
\(1\)
Given that
\(f(x)=∝sin^{2}3x\) and \( f'(\dfrac{\pi}{12})=-3\)
Then ,
\(f'(x)=2×3∝sin3x.cos3x\)
\(f'(x)=6∝sin3x.cos3x\)
Now, comparing the like terms we can write,
\(x=\dfrac{\pi}{12}\)
So,
\( f'(\dfrac{\pi}{12})=6∝sin3(\dfrac{\pi}{12}).cos3(\dfrac{\pi}{12})\)
\( ⇒ -3=6×∝×\dfrac{1}{√2}×\dfrac{1}{√2}\)
\( ⇒ -3=6×∝×\dfrac{1}{2}\)
\(⇒ ∝=-1\)
If \( x = a(0 - \sin \theta) \), \( y = a(1 + \cos \theta) \), find \[ \frac{dy}{dx}. \]
Find the least value of ‘a’ for which the function \( f(x) = x^2 + ax + 1 \) is increasing on the interval \( [1, 2] \).
If f (x) = 3x2+15x+5, then the approximate value of f (3.02) is
If some other quantity ‘y’ causes some change in a quantity of surely ‘x’, in view of the fact that an equation of the form y = f(x) gets consistently pleased, i.e, ‘y’ is a function of ‘x’ then the rate of change of ‘y’ related to ‘x’ is to be given by
\(\frac{\triangle y}{\triangle x}=\frac{y_2-y_1}{x_2-x_1}\)
This is also known to be as the Average Rate of Change.
Consider y = f(x) be a differentiable function (whose derivative exists at all points in the domain) in an interval x = (a,b).
Read More: Application of Derivatives