Question:

Let \(f(x)=αsin^{2}3x.\) If \(f'(π/12)=-3\) ,then the value of \(α \) is_____.

Updated On: Aug 1, 2023
  • \(-1\)

  • \(\pi\)

  • \(-\pi\)

  • \(0\)

  • \(1\)

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The Correct Option is A

Solution and Explanation

Given that

\(f(x)=∝sin^{2}3x\)  and   \( f'(\dfrac{\pi}{12})=-3\)

Then ,

\(f'(x)=2×3∝sin3x.cos3x\)

\(f'(x)=6∝sin3x.cos3x\)

Now,  comparing the like terms we can write, 

\(x=\dfrac{\pi}{12}\)

So, 

     \(    f'(\dfrac{\pi}{12})=6∝sin3(\dfrac{\pi}{12}).cos3(\dfrac{\pi}{12})\)

                       \( ⇒       -3=6×∝×\dfrac{1}{√2}×\dfrac{1}{√2}\)

                       \(  ⇒           -3=6×∝×\dfrac{1}{2}\)

                       \(⇒ ∝=-1\)

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Concepts Used:

Application of Derivatives

Various Applications of Derivatives-

Rate of Change of Quantities:

If some other quantity ‘y’ causes some change in a quantity of surely ‘x’, in view of the fact that an equation of the form y = f(x) gets consistently pleased, i.e, ‘y’ is a function of ‘x’ then the rate of change of ‘y’ related to ‘x’ is to be given by 

\(\frac{\triangle y}{\triangle x}=\frac{y_2-y_1}{x_2-x_1}\)

This is also known to be as the Average Rate of Change.

Increasing and Decreasing Function:

Consider y = f(x) be a differentiable function (whose derivative exists at all points in the domain) in an interval x = (a,b).

  • If for any two points x1 and x2 in the interval x such a manner that x1 < x2, there holds an inequality f(x1) ≤ f(x2); then the function f(x) is known as increasing in this interval.
  • Likewise, if for any two points x1 and x2 in the interval x such a manner that x1 < x2, there holds an inequality f(x1) ≥ f(x2); then the function f(x) is known as decreasing in this interval.
  • The functions are commonly known as strictly increasing or decreasing functions, given the inequalities are strict: f(x1) < f(x2) for strictly increasing and f(x1) > f(x2) for strictly decreasing.

Read More: Application of Derivatives