Question:
Let \(f(x) = \begin{cases} x+2 & for\ x\lt\ 1 \\ 4x-1 & for\ 1\leq x \leq3 \\ x^2+5 & for\ x\gt3 \end{cases}\). Then
Let \(f(x) = \begin{cases} x+2 & for\ x\lt\ 1 \\ 4x-1 & for\ 1\leq x \leq3 \\ x^2+5 & for\ x\gt3 \end{cases}\). Then
Updated On: May 31, 2024
- f(x) is not continuous at x=-1
- f(x) is continuous at x=1
- f(x) is continuous at x=3
- f(x) is not continuous at x=5
- f(x) is not continuous at x=2
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The Correct Option is B
Solution and Explanation
The correct option is (B) : f(x) is continuous at x = 1
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