Let \(f(x) = a^{3x}\) and \(a^5 = 8\). Then the value of \(f(5)\) is equal to:
Given the function \(f(x) = a^{3x}\) and the equation \(a^5 = 8\), we first need to find \(a\).
Since \(a^5 = 8\), we can solve for \(a\) as follows: \[ a = 8^{1/5} \] \[ a = 2^{3/5} \] Now, calculate \(f(5)\): \[ f(5) = a^{3 \times 5} = a^{15} \] Substitute \(a = 2^{3/5}\): \[ a^{15} = (2^{3/5})^{15} = 2^{(3/5) \times 15} = 2^9 = 512 \] Thus, \(f(5) = 512\).
The area bounded by the parabola \(y = x^2 + 2\) and the lines \(y = x\), \(x = 1\) and \(x = 2\) (in square units) is:
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: