Question:

Let \(f: R→ R\) be defined as \(f(x)=x^4\). Choose the correct answer.

Updated On: Sep 2, 2023
  • f is one-one onto
  • f is many-one onto
  • f is one-one but not onto
  • f is neither one-one nor onto
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The Correct Option is D

Solution and Explanation

\(f: R → R\) is defined as \(f(x)=x^4\).

Let \(x, y ∈ R\) such that \(f(x) = f(y)\).
\(⇒ x^4=y^4\)
\(⇒ x=±y\)
∴ \(f(x_1)=f(x_2)\) does not imply that \(x_1=x_2\)

For instance,
\(f(1)=f(-1)=1\)
∴ f is not one-one.

Consider an element 2 in co-domain R. It is clear that there does not exist any x in domain R such that \(f(x) = 2\).
∴ f is not onto.

Hence, function f is neither one-one nor onto.
The correct answer is D.

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Concepts Used:

Types of Functions

Types of Functions

One to One Function

A function is said to be one to one function when f: A → B is One to One if for each element of A there is a distinct element of B. 

Many to One Function

A function which maps two or more elements of A to the same element of set B is said to be many to one function. Two or more elements of A have the same image in B.

Onto Function

If there exists a function for which every element of set B there is (are) pre-image(s) in set A, it is Onto Function. 

One – One and Onto Function

A function, f is One – One and Onto or Bijective if the function f is both One to One and Onto function.

Read More: Types of Functions